Simplify sine squared theta divided by the quantity 1 minus sine squared theta.
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OpenStudy (anonymous):
@iPwnBunnies
OpenStudy (anonymous):
= sin^2 theta/cos^2 theta=tan^2 theta
OpenStudy (anonymous):
\[\frac{ Sin^2(\theta) }{ 1-\ Sin^2(\theta) }\]
OpenStudy (anonymous):
1
tan2 È
sin2 È
cos2 È
those are the answers
OpenStudy (anonymous):
You can use the identity:\[Cos^2(\theta) +Sin^2(\theta) = 1\]
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OpenStudy (anonymous):
so 1?
OpenStudy (anonymous):
yes...sure...its 1
OpenStudy (anonymous):
is it 1 bc sin theta cancels out
OpenStudy (anonymous):
Solving for Cos^2(theta) you see:\[\cos^2(\theta) = 1-\sin^2(\theta)\]
OpenStudy (anonymous):
No it is not 1.
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OpenStudy (anonymous):
Replace your new identity and you will find your solution.
OpenStudy (anonymous):
its tan^2(e) right?
OpenStudy (anonymous):
You have:\[\frac{ Sin^2(\theta) }{ 1-Sin^2(\theta) }\]
And know:\[Cos^2(\theta) =1 - Sin^2(\theta)\]
So replacing we now have:
\[\frac{ Cos^2(\theta) }{ Sin^2(\theta) }\]
OpenStudy (anonymous):
Another identity can now be used since we have similar exponents:
\[\frac{ Cos^n(\theta) }{ Sin^n(\theta) }=Tan^n(\theta)\]
Where n = exponent value
OpenStudy (anonymous):
Correct
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