Question

to prepare 300.0 mL of 0.2 M NaCl, how many grams of NaCl should be weighed out?

Answer 1

use the molarity formula: \(M=\dfrac{n_{solute}}{L_{solution}}\)

you can solve for moles then convert to mass, or substitute in \(n=\dfrac{m}{M_{molar}}\)

\(M=\dfrac{\dfrac{m}{M_{molar}}}{L_{solution}}=\dfrac{m}{M_{molar}*L_{solution}}\)


Rearranges to: \(m=M*M_{molar}*L_{solution}\)



Where:

\(M_{molar}\)=molar mass
m=mass
L=liters of solution
n=moles
M=molarity

Answer 2

@aaronq awesome work as usual!!!!!!!!

Answer 3

thank you!!!