Proof: Let A be an event. Then ∅ ⊂ A help by elucidating
Let A an arbitrary event, and since an empty set indicate no points, it is sound to point out that every point belonging to ∅ belongs to A
the empty set is a subset of every set vacuously so as \(A\subset B\iff x\in A\implies x\in B\)
that's the kind of notation I am looking for! thank you @satellite73
that is basically saying that the empty set is a subset of the event A The empty set is a subset of all sets
you know how to check it right? i mean the \(\LaTeX\)
I am a TEX newbie
\[A\subset B\iff\forall x, x\in A\implies x\in B\] would be more precise
right click and check what you need
Yes that is the definition of a subset. Every element that is in A is also in B ^
thanks also, @Miracrown
i did nothing tho
you participated LOL that's good enough
sureeee.... I was under the impression that the empty set was defined to be a subset of all sets. I am not really sure how to prove it A set with no elements is essentially a subset of any set because no element is also part of any other set
it is because of the definition that starts with IF \(x\in A\)
Ok, since x is not an element of the empty set, then that is by default false, and any implication that starts with F is by default true
spanks!
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