for a gas in a closed container its pressure is found to be 400 N/m^2 at 27 C. If temp raise to 54 C, what would pressure become? a 800 N/m^2 b 436 N/m^2. answer key says b but i say it is a
You can use the combined gas law or \(\large \sf PV=nRT\) to solve this. Here volume(V), number of moles(n) and universal gas constant(R) will be constant. So \(\large \sf P\propto T\)
Therefore, \(\hspace{10pt}\large \sf \frac{P_1}{P_2}=\frac{T_1}{T_2}\)
\(\bigstar\) Before moving further convert given temperatures into kelvin
Got it ?
ye thx i guess this problem required different thinking. I thought I could approach this like the other questions where if the temperature doubled i can use the ideal gas law and c that the pressure would double since they are proportional to eachother
I think u were not converting the temp into kelvins
U can apply the ideal gas law once u have converted the temps into kelvin. I have done the same thing
i guess the pressure wouldnt necessarily double since the volume would stay the same
But since, 27°C = 300K and 54°C = 327K. You can see that 327 is not actually double of 300
getting it ? don't compare the temperature given in the question. it is in centigrade.
o ok i am just trying to answer the question fast since i would have to when taking the exam. this question just looks very familiar to other questions where i would just compare the initial to end conditions and use the ideal gas equation to answer. thanks anyways
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