Question

A 76.5 kg cross-country skier skiing on unwaxed skis along dry snow at a constant speed of 4.00 m/s experiences a force of friction of -60.0 N. What is the coefficient of friction between unwaxed skis and dry snow?
a)0.08
b)0.78
c)1.28
d)12.5

Answer 1

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Answer 2

F (Force of Friction)= \(\mu\)mg, where \(\mu\)=coefficient of friction.

Answer 3

Set up the equation and find the value of \(\mu\)

Getting it ?

Answer 4

so μ=60N/(76.5kg*9.81m/s^2)
=0.08? @abhisar

Answer 5

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Answer 6

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