STATISTICS – HELP! Hypothesis Testing: ‘There is no difference between the products’ effectiveness’. 1)Using the variable Score A – Score B, conduct a two-tailed Z-test at the 5% significance level to determine if there is really a statistically significant difference between the effectiveness of each mouthwash. Check that the conditions are met to use the z-test. 2) Calculate the 95% confidence interval for the difference between the scores.
I'm having trouble with the confidence interval part...not sure which proportion to use... see table below, regarding "Eight of the volunteers were given mouthwash A first and then mouthwash B second. The other eight volunteers were given mouthwash B first and then mouthwash A second."
\[p^*-1.96\sqrt{\frac{ p^*(1-p^*) }{ n }} \le p \le p^*+1.96\sqrt{\frac{ p^*(1-p^*) }{ n }}\]
I know this formula, but im not sure what p* should be...
any ideas?
the null hypothesis is that the mean of Score A - Score B is zero
and you need to do a paired data test
the tricky part of the problem is that they change the order of the mouthwash
Is this a two sampZInt?
Well, it doesn't look like there are any proportions in this problem, it's just values. So you'd use the formula for that instead.
@BarbaraKara Can you post the entire question with all the english. there seems to be something missing
the samples are not independent samples, since it is the same person trying the two different mouthwashs
I mean each subject tries two different mouthwash
so i would do a 2 sample T test pooled or paired data.
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