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Mathematics
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OpenStudy (insa):
solve by completing the square or factorization:
x^2+2x+3=0
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OpenStudy (anonymous):
do you know the website mathway..?
OpenStudy (perl):
|dw:1405157269972:dw|
OpenStudy (insa):
no
OpenStudy (anonymous):
www.mathway.com ..?
OpenStudy (insa):
no lemmee see that..
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OpenStudy (insa):
hey thankxx... that website is really helpful :) :)
OpenStudy (anonymous):
glad to help.. xDDDD
OpenStudy (paki):
nice web,,, @russeldano
OpenStudy (perl):
is that website free?
OpenStudy (insa):
nope
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OpenStudy (paki):
mean @insa
OpenStudy (insa):
the website ain't free :/
OpenStudy (paki):
lol... then what is the benefit of that...?
OpenStudy (insa):
lol at least u get the correct answer
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OpenStudy (anonymous):
hehe.. gee tnx.. im sharing what other people did to me.. xDDDD what did u mean free..?
OpenStudy (neer2890):
\[x ^{2}+2x+3=0\]
\[x ^{2}+2x+(\frac{ 2 }{ 2 })^{2}+3-(\frac{ 2 }{ 2 })^{2}=0\]
\[(x+1)^{2}+3-1=0\]
\[(x+1)^{2}=-2\]
\[x+1=\pm \sqrt{-2}\]
\[x= \pm 2i-1\]
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