A potter's wheel, with rotational inertia 46 kg∙m2, is spinning freely at 40 rpm. The potter drops a lump of clay onto the wheel, where it sticks a distance 1.2 m from the rotational axis. If the subsequent angular speed of the wheel and clay is 32 rpm what is the mass of the clay?

Question

vincent-lyon.fr · Answer

Tip: Use conservation of angular momentum.

anonymous · Answer

I see the formula is 
L = r*m*v, but I'm confused about what is L in my question

anonymous · Answer

Initial angular momentum = final angular momentum  u knw  L is also =  I*W

anonymous · Answer

46 * 40  =   ( 46 + m* (1.2)^2 ) * 32

find  m

anonymous · Answer

Thanks for your help yahoo!