Find the value f ' (0) to determine if f(x) is differentiable at x=0
\[f(x)=x ^{1/3}+2\]
ok first I was asked to graph the function second I was asked if f(x) is continuous at x=0
so I did the graph, no problem yes f(x) is continuous at x=0
I took the derivative and the derivative should be undefined
is f continuous at 0? or is f right continuous at 0?
what do you mean f right continuous at o?
isn't actually left continuous nothing exists to the left for it to be continuous at x=a you must have: 1)\[\lim_{x \rightarrow a}f(x) \text{ exists }\] 2) \[f(a) \text{ exists }\] finally 3) \[\lim_{x \rightarrow a} f(x)=f(a)\] can you answer number 1?
oh is that not a 1/2 power?
I cannot read latex I swear
3 and 2 look like
|dw:1405179161748:dw|
the power is (1/3-1)
but also song that does not give f' is 0 at x=0 \[\frac{1}{3x^\frac{2}{3}}\]
I thought I was looking at the wrong graph
it is x to the (1/3) power plus 2
Yea sorry @precal I thought I was seeing 1/2 not 1/3 :( my bad
i have to take my cat to the vet i will bb
ok here is where I got very confused. I did this by hand and then I used my graphing calculator to verify the solution and it gave me 100 well that is very confusing or maybe I found a function where the calculator gives an incorrect solution
thanks @myininaya hope your cat feels better. Mine never like going to the vet. She did live for about 20 years. The best cat ever.....
the first thing is need to prove (right =left ) continuous ,and then diferenationate
well the f(0)=2 the point exists, and the limit exists at 2 approaching zero from both sides
yes
no f ' (0) does not equal zero that implies that f ' (0) has a horizontal tangent at x=0 and it clearly does not
|dw:1405180427457:dw|this is the graph of the derivative
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