The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent?
The coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds. The coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds. The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds. The coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.
@ninjasandtigers
x/t is speed. So the rate of change will be related to speed. At t=3; the coin is falling at 29.4m/s and at t-6; the coin is falling at 58.8m/s. If you take these and add them together, then divide by 2, you'll get rate per 3 seconds. Divide by 3 and you get 14.7m/s.
that means its A?
OR C?
i think d
ok thanks i have one more question :))))
Determine which of the following statements is true concerning the values described in column #1 and column #2. Column #1 Column #2 The x-coordinate of the vertex of the graph of y = -2×2 – 4x + 12 The x-coordinate of the vertex of the graph of y = x2 – 4x + 3 The value found in column #1 is greater than the value found in column #2. The value found in column #1 is less than the value found in column #2. The value found in column #1 is equivalent to the value found in column #2. The relationship between column #1 and column #2 cannot be determined by the information given.
a
thanks
welcome :)
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