Chemistry
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OpenStudy (lovelyharmonics):
If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced?
2 KClO3 → 2 KCl + 3 O2
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OpenStudy (lovelyharmonics):
@ganeshie8
OpenStudy (lovelyharmonics):
My options are
15.5 g O2
23.2 g O2
31.0 g O2
46.4 g O2
ganeshie8 (ganeshie8):
start by finding the molar mass of KCLO3 :
K : 39.1
Cl : 35.45
O3 : 16*3 = 48
-----------------
KCLO3 : 39.1 + 35.45 + 48 = 122.55 g/mol
ganeshie8 (ganeshie8):
tell me, how many mols are present in 59.3 grams of KCLO3 ?
OpenStudy (lovelyharmonics):
2.1
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ganeshie8 (ganeshie8):
Nope.
122.55 g has 1 mol
how can 59.3g be more than 1 mol ?
OpenStudy (lovelyharmonics):
.-. 122.55/59.3..... 59.3+59.3=118.6
OpenStudy (lovelyharmonics):
118 fits into 122
ganeshie8 (ganeshie8):
\[\large \text{59.3 g} = \text{59.3 g} \times \dfrac{\text{1 mol }}{\text{122.55 g}} = 0.484 ~\text{mol}\]
OpenStudy (lovelyharmonics):
.-. Wtf.... Where did that just come from
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ganeshie8 (ganeshie8):
`KCLO3 : 39.1 + 35.45 + 48 = 122.55 g/mol`
1 mol = 122.55 g
ganeshie8 (ganeshie8):
? mol = 59.3 g
ganeshie8 (ganeshie8):
thats the question.
ganeshie8 (ganeshie8):
lets try this :
1 mol = 122.55 g
so, 1g = 1/122.55 mol right ?
OpenStudy (lovelyharmonics):
Yus
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ganeshie8 (ganeshie8):
finally a yes xD
1g = 1/122.55 mol
multiply both sides by 59.3, what do u get ?
OpenStudy (lovelyharmonics):
0.484
ganeshie8 (ganeshie8):
1g = 1/122.55 mol
59.3 g = 59.3/122.55 mol
= 0.484 mol
ganeshie8 (ganeshie8):
that means you have `0.484 mol of KCLO3 ` in the reaction, lets see how much O2 this produces
OpenStudy (lovelyharmonics):
And how do I do that .-.
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ganeshie8 (ganeshie8):
2 KClO3 → 2 KCl + 3 O2
KClO3 → KCl + 3/2 O2
ganeshie8 (ganeshie8):
multiply through by 0.484
OpenStudy (lovelyharmonics):
.-. Multiply what through
ganeshie8 (ganeshie8):
0.484KClO3 → 0.484 KCl + `0.484*3/2` O2
ganeshie8 (ganeshie8):
So it produces 0.484*3/2 mol of O2
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ganeshie8 (ganeshie8):
convert mols to grams, and you're done!
ganeshie8 (ganeshie8):
0.484*3/2 mol of O2 = How many grams ?
OpenStudy (lovelyharmonics):
0.726 c:
ganeshie8 (ganeshie8):
yes
0.726 mol of O2 = How many grams ?
ganeshie8 (ganeshie8):
whats the molar mass of O2 ?
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OpenStudy (lovelyharmonics):
.-. I have no idea
ganeshie8 (ganeshie8):
google
OpenStudy (lovelyharmonics):
N c: just use your stuff from up top. 16*2=32
OpenStudy (lovelyharmonics):
*no
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ganeshie8 (ganeshie8):
that works !
1 mol of O2 = 32 grams
ganeshie8 (ganeshie8):
0.726 mol of O2 = How many grams ?
OpenStudy (lovelyharmonics):
1/32=0.726/?
232.32/1
OpenStudy (lovelyharmonics):
I'm guessing mines wrong and the correct answer is 23.2
ganeshie8 (ganeshie8):
tell me this :
if 1 coconut weighs 1 kg
then half coconut weighs how many kg ?
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OpenStudy (lovelyharmonics):
That's the great thing about multiple choice right there XD
ganeshie8 (ganeshie8):
23.2 is correct !
OpenStudy (lovelyharmonics):
.5kg....
ganeshie8 (ganeshie8):
how did u get .5kg ?
ganeshie8 (ganeshie8):
you multiplied the original weight by 1/2 right ?
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OpenStudy (lovelyharmonics):
By halfing it .-.
OpenStudy (lovelyharmonics):
Well I don't really need to go through the whole process of 1*1/2=.5
OpenStudy (lovelyharmonics):
But yeah I guess what your sayin
ganeshie8 (ganeshie8):
then tell me this, how much 0.235 of coconut weighs ?
ganeshie8 (ganeshie8):
how much \(\large \pi \) of coconut(s) weigh ?
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ganeshie8 (ganeshie8):
how much 10 coconuts weigh ?
ganeshie8 (ganeshie8):
this is essentially a multiplication problem, not a division problem. okay ?
OpenStudy (lovelyharmonics):
Yeah it's cross multiplication that's what I did
ganeshie8 (ganeshie8):
okay nice :) anything is fine as long as it makes sense...