Eliminate the parameter. x = 3 cos t, y = 3 sin t im so confused, can someone please explain and tell me the steps
can you show me the work? i dont really understand what you mean. I have the answer, I just dont understand how to solve it @mayankdevnani
yes
@mayankdevnani
did you write something?.. @mayankdevnani
@wade123 just divide both equationss because to cancel out 3:- we get, \[\huge \sf \frac{x}{y}=\frac{3cost}{3sint}=tant\] finally we get, \[\huge \sf x=y~tant\]
understood? @wade123
you said something before about equaling it to t.. @mayankdevnani
noo...just forgot my comment and just concentrate in my new comment and if you have any problem regarding my new comment,please reply
what is tant... @mayankdevnani
@ganeshie8 please help!
\[\huge \sf tant=\frac{sint}{cost}\]
its wrong.......its \[\huge \sf \cot t\]
this is tricky, `t` is still there, try this may be x = 3 cos t, y = 3 sin t x^2 = 9 cos^2t y^2 = 9 sin^2t -------------------- x^2 + y^2 = 9(sin^2t + cos^2t)
recall the identity : sin^2t + cos^2t=1 x^2 + y^2 = 9(1) x^2 + y^2 = 9 this is just a circle !
@ganeshie8 what about my answer??
see if that makes more or less sense..
which answer ?
\[\huge \sf x=y \cot t\]
`t` still exists right ?
in the final equation, `t` should not be present...
ohhh
Join our real-time social learning platform and learn together with your friends!