Question

C 70.55 % H 10.66 % O 18.80 %
Enter the subscripts of the empirical formula.

The next step is to determine the molecular formula from mass spectrum. The laboratory sent these results:
formula weight was found between 168.24 and 173.24
Enter the subscripts of the molecular formula. If one of the subscripts is 1, you must enter it here -- although this is not normal

Answer 1

Make sure the sum of percentages add up to 100%. Note % as mass (g)
C H O
70.55g 10.66g 18.80g
Divide Each element by their molar mass
70.55/12 10.66/1 18.80/16
5.879166 moles of C 10.66 moles of H 1.175 moles of O
Divide by the smallest figure which is 1.175
5.879/1.175 10.66/1.175 1.175/1.175
5.00-C 9-H 1-O
C5H9O-This is the smallest whole ratio Empirical Formula

Answer 2

I think you should take the average value by adding 168.24 and 173.24 and divide by 2
we get 170.74 gram
170.74=85x, x is the factor multiplied by the empirical mass to obtain the molecular mass.
x=2

Answer 3

the second one have to be in this form please
C H O

Answer 4

Molecular formula- C10H18O2

Answer 5

thank you so much please what is your real name and you are so kind

Answer 6

please can you help with other question?