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Chemistry 21 Online
OpenStudy (somy):

Chemistry calculations review

OpenStudy (somy):

@aaronq ❤

OpenStudy (somy):

im forgetting some stuff apparently which is obviously not good <.< so help me remember ❤

OpenStudy (aaronq):

kk :)

OpenStudy (somy):

now Limiting reagent if you are given 2 moles (of 2 reactants) and along with that you are given unbalanced reaction

OpenStudy (somy):

how do i know which reactant is limiting?

OpenStudy (somy):

i thought i can just say it by looking at moles given smallest- limiting

OpenStudy (aaronq):

so lets say you have 2 A + 3 B -> 2 C and you have 2 moles of A and 2 moles of B. You can do it logically or you can divide the moles of each by their coefficient. This is analogous to normalizing something (statistically speaking). So we have \(\dfrac{n_{A}}{2}=\dfrac{2}{2}= 1~ mole\) and \(\dfrac{n_{B}}{2}=\dfrac{2}{3}=0.666~moles\) we can now see that there are less moles of B once we take the coefficients into acowingspan.

OpenStudy (aaronq):

into account***

OpenStudy (somy):

ohhh

OpenStudy (somy):

i seeee

OpenStudy (somy):

you did a good job @aaronq !!! lol

OpenStudy (aaronq):

haha thanks, anything else?

OpenStudy (somy):

remembered lol

OpenStudy (somy):

yes

OpenStudy (somy):

this one is a teeny -tiny confusion

OpenStudy (somy):

if you are given a mass of something then you are asked to find mole of it when i take its Molecular mass, do i consider coefficient of that 'compound/element' ?

OpenStudy (aaronq):

like in terms of the coefficient of the balanced chemical reaction? no, you dont.

OpenStudy (somy):

okaay good now everything is clear :3

OpenStudy (aaronq):

wooo

OpenStudy (somy):

thank you ❤❤❤❤❤❤

OpenStudy (aaronq):

no problem!

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