A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance? Answer: ____ J/g•K
E = m × c × θ E is the energy transferred in joules, J m is the mass of the substances in kg c is the specific heat capacity in J / kg °C θ (‘theta’) is the temperature change in degrees Celsius, °C 345.2=89.5*c*((305-273)-(285-273)) we subtract by -273 to change from kelvin to degree Celsius
oh sorry i did a mistake dont change the unit leave it as it is because you need the units in kelvin iam sorry (305-285)
Question. Is the equation you gave me "E = m × c × θ", the same as the equation "q=mCp△T"?
it is, he just used different symbols
true true
Ah okay. I see now. Thank you.
Your Welcome :)
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