A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?

Answer: ____ J/g•K

Question

A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?

Answer: ____  J/g•K

abmon98 · Answer

E = m × c × θ
E is the energy transferred in joules, J
m is the mass of the substances in kg
c is the specific heat capacity in J / kg °C
θ (‘theta’) is the temperature change in degrees Celsius, °C
345.2=89.5*c*((305-273)-(285-273))
we subtract by -273 to change from kelvin to degree Celsius

abmon98 · Answer

oh sorry i did a mistake dont change the unit leave it as it is because you need the units in kelvin iam sorry 
(305-285)

anonymous · Answer

Question.
Is the equation you gave me "E = m × c × θ", the same as the equation "q=mCp△T"?

aaronq · Answer

it is, he just used different symbols

somy · Answer

true true

anonymous · Answer

Ah okay. I see now. Thank you.

abmon98 · Answer

Your Welcome :)