Find the value of x in the figure below if the volume is 232,789.58 mm3.http://static.k12.com/eli/bb/817/-1/0/2_36860_44974/-1/1a00ea5b932a526fd3f3dc71ca188f09d627c9b3/media/2350e72ec423ac38aecc3443af98c928433f7a35/mediaasset_652489_1.jpg
I can walk you through it but I am not gonna do it for you.
that would be great. I thought i went through the process right but the answer i came up with wasn't one of the choices
The key here is to solve for the vplume first and then after getting the volume, you can solve backwards for x by using a different formula for the area of the triangle. Are you getting what I am saying?
okay i get what your saying but how do i solve for the volume if i cant solve the area of the triangle (the base)
there is a formula for the area of an equilateral triangle. its x^2 (sqrt(3))/4. You have the value of x which is any of these sides because all fo the sides are equal/
so after you get the volume for the shape. You add the areas of both of the rectangles and the triangles and you should be able to solve for x from there.
okay so the formula for the area of an equilateral triangle would look like \[24.5^{2}(3/4)\]
yes, times it by 2, get the area of one rectangle and times it by 3 that should give you the volume. Then use the volume to solve for the other side that is missing.
okay so the area of the triangle, i got 450.19. For the area of the rectangle i got 1847.3. i multiplied the triangle area by 2 and got 900.38 and the rectangle area by 3 and got 5,541.9 which comes to the total of 6,442.28. Is that correct?
@Boblovesmath
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