Question

HELP PLEASE!!!!!
Xavier is riding on a Ferris wheel at the local fair. His height can be modeled by the equation H(t) = 20 cospi over 15 + 30, where H represents the height of the person above the ground in feet at t seconds.

Answer 1

Part 1: How far above the ground is Xavier before the ride begins?
Part 2: How long does the Ferris wheel take to make one complete revolution?
Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?

You must show all work

Answer 2

@IMStuck

Answer 3

@nikato

Answer 4

@Cosmichaotic

Answer 5

@IMStuck

Answer 6

@triciaal

Answer 7

@MaimiGirl

Answer 8

part 1 is asking what is h when t = 0

Answer 9

so 30 right?

Answer 10

are you sure you have the eqn written correctly. H (t) but no t in the expression
20 cos pi/15 = 0

Answer 11

Sorry. H(t)=20cos(pi/15)t+30

Answer 12

ok now you have the funnction
when t = 0 h = 30 yes

Answer 13

what about part 2 and 3

Answer 14

find what is the value of t when h = 0.

Answer 15

how do you do that

Answer 16

set the function =0

Answer 17

H(t) =( 20 cospi over 15) t+ 30 = 0

Answer 18

So t=1.5

Answer 19

sorry -1.5

Answer 20

let me try to get some more input . not very fast with this anymore.

Answer 21

@Kainui can you help with this?

Answer 22

can you help @Kainui

Answer 23

ANYONE!!!!!!

Answer 24

@OOOPS

Answer 25

let @Kainui help. He is better than me, hihihi

Answer 26

when t =0 H(t) = 50 because cos 0 =1

Answer 27

the equation of the height is H(t) =\(20cos(\dfrac{\pi t}{15})+30\) right?

Answer 28

confirm or correct this equation, please

Answer 29

Anyway, I think the net is down so that you can't reply
for b) take derivative and let it =0, solve for t, (the reason is finding the max and min of the graph) then times that t by2 to get the answer

Answer 30

for c) the min is one of the roots we get from b) replace the value of min into the H(t) to get the height at min, and then at max, heigh max-heigh min= answer