Help me please! I need help on my algebra II. How would I do this question? [(2)/(x^2-9)]-[(3x)/(x^2-5x+6)]

Question

neer2890 · Answer

$$\frac{ 2 }{ x ^{2}-9 }-\frac{ 3x }{ x ^{2}-5x+6 }=\frac{ 2 }{ x ^{2}-3^{2} }-\frac{ 3x }{ x ^{2}-3x-2x+6 }$$

neer2890 · Answer

$$=\frac{ 2 }{ (x+3)(x-3) }-\frac{ 3x }{ x(x-3)-2(x-3) }=\frac{ 2 }{ (x+3)(x-3) }-\frac{ 3x }{ (x-2)(x-3) }$$

neer2890 · Answer

$$=\frac{ 1 }{ (x-3) } [\frac{ 2 }{ x+3 }-\frac{ 3x }{ x-2 } ]$$

neer2890 · Answer

$$=\frac{ 1 }{ (x-3) }[\frac{ 2(x-2)-3x(x+3) }{ (x+3)(x-2) }]=\frac{ -3x ^{2}-7x-4 }{ (x-3)(x+3)(x-2) }$$

anonymous · Answer

@neer2890  Thank you! How do I give you a medal?

neer2890 · Answer

$$=\frac{ -3x ^{2}-3x-4x-4 }{ (x-2)(x-3)(x+3) }=\frac{ -3x(x+1)-4(x+1) }{ (x-2)(x-3)(x+3) }$$

neer2890 · Answer

$$=\frac{ (-3x-4)(x+1) }{ (x-2)(x-3)(x+3) }$$
you're welcome...:)