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solve (15(0.95)^(n+1))=20(0.94)^(n),n
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Is this the equation? \(\large 15(0.95)^{n + 1} = 20 (0.94^n) \)
Yes
First, divide both sides by 20.
It okay, I solved it
\(\large 0.75(0.95)^{n + 1} = 0.94^n\) \(\large 0.75(0.95^n)(0.95) = 0.94^n\) \(\large (0.95)(0.75)(0.95^n) = 0.94^n\) \( \large( \dfrac{0.95}{0.94} \large)^n = 0.95^{-1}0.75^{-1} \) \(\large \ln (\dfrac{0.95}{0.94}\large)^n = \ln (0.95^{-1}0.75^{-1} \)) \(n\ln \dfrac{0.95}{0.94} = -\ln 0.95 - \ln 0.75 \) \(n( \ln 0.95 - \ln 0.94) = -\ln 0.95 - \ln 0.75 \) \(n = \dfrac{-\ln 0.95 - \ln 0.75}{ \ln 0.95 - \ln 0.94 } \)
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\(n = -\dfrac{\ln 0.95 + \ln 0.75}{ \ln 0.95 - \ln 0.94 }\) \(n \approx 32.033\)
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