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Physics 12 Online
OpenStudy (anonymous):

Please help me solve this question.A truck of mass 4000kg travelling at 72km/h collides into a car mass 1000kg which is rest.The two vehicles move together after collision.What is the kinetic energy of truck after collision?

OpenStudy (abhisar):

Hello @MichelleShum ! \(\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\\\color{white}{.}\\\Huge\color{blue}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}\\\color{white}{.}\\\\\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\)

OpenStudy (abhisar):

Do u know about Conservation of Linear Momentum ?

OpenStudy (abhisar):

\(\hspace{30pt}\huge \sf \ Conservation \ of \ Linear \ Momentum\) It states that in a closed system (one that does not exchange any matter with the outside and is not acted on by outside forces) the total momentum is constant. Mathematically, \(\large\sf \ M_1U_1+M_2U_2=M_1V_1+M_2V_2\)

OpenStudy (abhisar):

Here, \(\sf M_1=4000kg \\ M_2=1000kg \\ U_1=72km/hr \\ U_2=0km/hr\)

OpenStudy (abhisar):

Now after collision both the car and truck moves together so \(\sf V_1=V_2\). Now set up the equation and find the value of \(\sf V_1\). After that use the formula of kinetic energy i.e K.E=\(\large \sf \frac{1}{2}mv^2\) to find the kinetic energy of truck.

OpenStudy (anonymous):

Ok...Thank you very much...I'm actually don't understand the whole topic about momentum...Hope if u have time,please explain and teach me about this topic...

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