Find the point on the terminal side of θ = 3π/4 that has a y coordinate of 1. Can somebody walk me through this? I don't really understand.
ur point is in the second coordinate
right?
3π/4=π/2+π/4
OK, I think I partly solved the problem. Would you mind telling me if I am correct or not?
ok go on
Using the unit circle, we know that the line on the second quadrant comes together with the line of the terminal side of θ to create a 45 degree angle. Am I correct so far?
u r right
Next, since I know the length of the side of the triangle is 1 (y=1).
I can use the tan function to get the other side. tan 45 = 1/x.
ya
x is the adjacent side of θ that we are looking for.
so x = 1?
and that solved the problem, right?
u know ur point is in the second quadrunt
x=-1
Oh, I am confused now. How would that get along with the equation?
Like tan 45 = 1/x. How do I get x = -1 on that?
Or I will just get x = 1 and then tell since it's in the second quadrant, x = -1?
u know all value of x in the second quadrunt in negative
So I will go with "I will just get x = 1 and then tell since it's in the second quadrant, x = -1" ?
ys
OK, I got it. Thank you so much for sticking with me. I appreciate it a lot!
i also enjoyed it
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