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Physics 13 Online
OpenStudy (anonymous):

(a) Consider 3 objects of equal masses. Picture these objects experience combinations of different applied forces, However, this time include different applied forces, f1, f2. Find the net force on each object. (b) If each of the objects above were to be opposed by an external force, such that, they would decelerate to rest, indicate the relative sizes of these deceleration forces necessary to oppose the net force. (c) From above, rank the magnitudes of the decelerations necessary to stop the objects in motion

OpenStudy (anonymous):

ok so far I have: 3 objects are equal to 12Kg ( Applied Forces) Object 1: Applied Forces are 5N<------>10N Object 2: Applied Forces are 6N<------> 12N Object 3: Applied Forces are 10N<----->20N (Net Forces) Object 1: = 5 Newtons Object 2: = 6Newtons Object 3: 10Newtons Force = Mass * Acceleration

OpenStudy (ipwnbunnies):

Ok, so the forces are pulling in the exact opposite directions? That's what I was confused about. There are virtually infinite ways the two forces can be acting on the objects, so there would be virtually infinite ways to decelerate it.

OpenStudy (anonymous):

I am very confused... This is my first time taking Physics 102 and I am struggling more than I anticipated

OpenStudy (anonymous):

well here since there isnt the same amount of force acted upon each object from both directions then their isn't equilibrium present

OpenStudy (abhisar):

Lets deal with it one by one.

OpenStudy (anonymous):

ok !!

OpenStudy (abhisar):

First consider the case (a)

OpenStudy (abhisar):

Do we have to take three objects one y one or simultaneously ?

OpenStudy (abhisar):

*by

OpenStudy (anonymous):

Teachers comment: From (1)(a)-(b) above, rank the magnitudes of the decelerations necessary to stop the objects motion so I guess Simultaneously

OpenStudy (abhisar):

Is this the answer u have got ? \(\color{blue}{\text{Originally Posted by}}\) @Ms.Castillo ok so far I have: 3 objects are equal to 12Kg ( Applied Forces) Object 1: Applied Forces are 5N<------>10N Object 2: Applied Forces are 6N<------> 12N Object 3: Applied Forces are 10N<----->20N (Net Forces) Object 1: = 5 Newtons Object 2: = 6Newtons Object 3: 10Newtons Force = Mass * Acceleration \(\color{blue}{\text{End of Quote}}\)

OpenStudy (anonymous):

this is my start to answering the assignment so basically (part a) but part b is where I am stuck

OpenStudy (abhisar):

okay i got it. So u have taken second force in opposite direction for every object.|dw:1405270164455:dw|

OpenStudy (anonymous):

yes in order to get the net force

OpenStudy (abhisar):

ok now let's see the second part of ur question. I'll do it for one object in order to give uh an example.

OpenStudy (anonymous):

thank you!! so do I have part a correct?

OpenStudy (abhisar):

Yes it is correct. But as @iPwnBunnies said two force can act on an object in infinite way. So net force can also be 15 N. It all depends upon the orientation of two forces.

OpenStudy (anonymous):

ohhh ok I see we can either add the two forces together or subtract

OpenStudy (anonymous):

so can let me ask you, Subtracting them means what exactly?

OpenStudy (anonymous):

does it mean the objects are pulled in opposite direction instead of same direction? adding together means same direction VS Subtracting which means opposite direction?

OpenStudy (abhisar):

Basically net force for two forces say A & B = \(\large \sf \sqrt{A^2+B^2+2ABcos\theta}\), where \(\sf \theta\) is the angle between two forces A & B

OpenStudy (abhisar):

\(\color{blue}{\text{Originally Posted by}}\) @Ms.Castillo does it mean the objects are pulled in opposite direction instead of same direction? adding together means same direction VS Subtracting which means opposite direction? \(\huge\checkmark\) \(\color{blue}{\text{End of Quote}}\)

OpenStudy (abhisar):

Got it ?

OpenStudy (anonymous):

kinda confused on your diagram

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