A pencil is located 15 cm from a concave lens with a focal length of 30 cm. Where is the image located? A. -10 cm B. 30 cm C. 10 cm D. -30
I think it is A?
use the same formula, this time take f=-30
so then A?
\(\huge \sf \frac{1}{-30}=\frac{1}{-15}+\frac{1}{v}\), now find V
are you even sure that they are negatives cause their not negatives in the problem?
They will never give u in the problem. You will have to put the negative/positive sign according to cartesian sign convention by urself
So C?
u solved the equation ?
i think so?
\(\huge \sf \frac{1}{-30}=\frac{1}{-15}+\frac{1}{v}\), \(\huge \sf \frac{1}{-30}+\frac{1}{15}=+\frac{1}{v}\), \(\huge \sf \frac{2-1}{30}=+\frac{1}{v}\),
So, V= ?
B?
\(\huge\checkmark\)
thanks (:
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