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Physics 16 Online
OpenStudy (anonymous):

A pencil is located 15 cm from a concave lens with a focal length of 30 cm. Where is the image located? A. -10 cm B. 30 cm C. 10 cm D. -30

OpenStudy (anonymous):

I think it is A?

OpenStudy (abhisar):

use the same formula, this time take f=-30

OpenStudy (anonymous):

so then A?

OpenStudy (abhisar):

\(\huge \sf \frac{1}{-30}=\frac{1}{-15}+\frac{1}{v}\), now find V

OpenStudy (anonymous):

are you even sure that they are negatives cause their not negatives in the problem?

OpenStudy (abhisar):

They will never give u in the problem. You will have to put the negative/positive sign according to cartesian sign convention by urself

OpenStudy (anonymous):

So C?

OpenStudy (abhisar):

u solved the equation ?

OpenStudy (anonymous):

i think so?

OpenStudy (abhisar):

\(\huge \sf \frac{1}{-30}=\frac{1}{-15}+\frac{1}{v}\), \(\huge \sf \frac{1}{-30}+\frac{1}{15}=+\frac{1}{v}\), \(\huge \sf \frac{2-1}{30}=+\frac{1}{v}\),

OpenStudy (abhisar):

So, V= ?

OpenStudy (anonymous):

B?

OpenStudy (abhisar):

\(\huge\checkmark\)

OpenStudy (anonymous):

thanks (:

OpenStudy (abhisar):

\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)

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