Question

4. What is the possible discriminant of the graph?

a parabola opening up with vertex near negative 1.2 comma negative 9.1. a y intercept of negative 6

-11
zero
25
73

5. What is the possible discriminant of the graph?

a parabola opening up x intercepts near negative 7 and negative 3

-13
zero
15
16

Answer 1

@phi @aaronq

Answer 2

@Zarkon @dan815

Answer 3

@radar @iambatman

Answer 4

@e.mccormick

Answer 5

@shamil98 @radar plz

Answer 6

@zzr0ck3r

Answer 7

@Kainui pretty plz i need help

Answer 8

For 5 i got 16...still working on 4. I know 5 is correct.

Answer 9

Really are u sure about 5

Answer 10

how did u get 16?

Answer 11

I am sure about 5. The value of the discriminant comes out to 16. Use the x intercepts to find the quadratic that these two intercepts create, like this:

Answer 12

\[(x+3)(x+7)=x ^{2}+10x+21\]The discriminant part of that is \[(10)^{2}-4(1)(21)=16\]The math doesn't lie.

Answer 13

@superhelp101 You need to post the graph.
Depending on the value of the leading coefficient, the value of the discriminant varies.
If a is the leading coefficient, the discriminant is \(16a^2\).

Answer 14

For #4, here's what I did: I figured the quadratic from the x^2 part of the equation, which was (x+ 1.2)^2. FOILing that out gave an equation of \[x ^{2}+2.4x+1.44\]The discriminant part of that is:\[(2.4)^{2}-4(1)(1.44)=0\]

Answer 15

Can't read the x intercepts on graph 1. Can you tell me what they are?

Answer 16

(-3.306, 0) and (.806,0)

Answer 17

For question 2,
f(x)=a(x+3)(x+7)
and f(-5)=-4, so a = 1, yes, @IMStuck has the right answer of discriminant = 16(1^2)=16.

Answer 18

Ok, then, redo on the #4...

Answer 19

Alright

Answer 20

The quadratic equation for #4 is \[x ^{2}+2.5x-2.6646\]and the discriminant part for that is:

Answer 21

\[(2.5)^{2}-4(1)(-2.6646)=16.89\]That one I'm not seeing in your answers. Maybe @mathmate could lend his eyes to this?

Answer 22

oh. Could you help me @mathmate

Answer 23

Try
f(x)=a(x-0.806)(x+3.306)
and use f(-1.25)=-9.1 or f(0)=-6 to find a = 2.2517
You should get discriminant equal to 78.73 or 85.76 (instead of 73).
I believe we discussed this one before.