how do we Rank the forces of static friction necessary to accelerate an objects mass from being at rest?

Question

ipwnbunnies · Answer

$$Frictional force = \mu_{s} F_{N}$$
This the frictional force to start an object.

Where µs is the coefficient of static friction of certain objects.
And Fn is the normal force, the force the "ground" pushes on an object.

ipwnbunnies · Answer

So, let's say we had different objects on the same surface. If we wanted to accelerate each from rest, they would all take some static frictional force we must overcome. On a flat surface, Fn would be numerically equivalent to the weight of the object.

Therefore, the more massive the object, the more static frictional force it has, the more you would have to overcome to accelerate it.

anonymous · Answer

wow!! I understand it!! so can you further help me?

anonymous · Answer

I think to 'rank' is wrongly put. You may have different values to static friction force by changing the variables of the formula Frictionalforce=μsFN (as iPwnBunnies wrote). It is a force that  acts in the contact between the object and the surface where it is.
 One thing is, the formula gives the maximum force you need to apply so the object start moving, and it can change if you change the mass of the object or the surface (μs).

i. The force is opposite to the movement, or the force you apply so the object move. It increases untill the maximum value is reached.
ii. The area of contact is not a variable of the formula, so the frictional force doesn't depend on the area.

To make clear: the formula gives the maximum force parallel to the movement, but while you try to pull the object, there is an opposite force, with same intensity of yours (if it reaches the maximum, the object starts to move).

anonymous · Answer

Thank you Siedi.yamauti!! Your explanation is clear, I truly appreciate your help =)