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suppose 2.4mol of reactant B react with excess reactant A. How many moles of the product can form?
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\[x_2 + 6y_2x \rightarrow 4x_2y_3\] Here's the equation!
help anybody?
Look at the mole ratio of reactants x2+6y2x→4x2y3 1:6 this indicates that only y2x is in excess and x2 is the limiting reagent. this means that only 2.4 moles is consumed. so we use 2.4 as the number of moles. look at the mole ratio of x2 to 4x2xy3 1:4 2.4:x x=2.4*4/1
so there will be 9.6mol of the product?
yes
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thank you!
your welcome.
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