Question

what is the vertex form of y=(x+2)(x-3)?

Answer 1

y=(x+2)(x-3)
y=x^2 - x -6
try completeing squares first

Answer 2

First expand:
\[(x+2)(x-3)=x^2-x-6\]
Complete the square to write the parabola in vertex form:
\[x^2-x+\frac{1}{4}-\frac{25}{4}=\cdots\]

Answer 3

so you = it to zero and add 6 to both sides

Answer 4

no
see what SithsAndGiggles has done for completing the squares
y =x^2 - x -6
y = x^2 -2*(1/2) x +1/4 -1/4 -6
y=(x-1/2)^2 -25/4
or y+25/4 = (x-1/2)^2
now i hoep you may be able to sate the vertex

Answer 5

so the vertex of the parabola right?

Answer 6

1/2 ,-25/4

Answer 7

so now what ?

Answer 8

The vertex form of a parabola's equation is generally expressed as :
y= a(x-h)2+k
where (h, k) is the vertex

Answer 9

so do i plug in the 1/2 and -25/4 into the equation?

Answer 10

yes
y = (x-1/2) -25/4

Answer 11

another approach
after you expand and you have y = x^2-x - 6
a = 1 b = -1 and c = -6
the h value for the vertex = -b/2a = -(-1)/2*1 = 1/2
the k value is f(h) = (1/2)^2 -1/2 - 6 = 1/4 -1/2 -6 = -25/4

Answer 12

so how do i put it into vertex form?

Answer 13

repost
yes
y = (x-1/2)^2 -25/4