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How would this further simplify
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wait
lol i hope not to sleep untill u post :P *waiting*
\[\huge \frac{ cosecxcotx +cosec ^{2}x }{ (cosecx + cotx)^{2} }\]
if you doing integration sum then simply use cosecx+cotx = z and then proceed
this is already differentiated , how would this fraction simplify the answer is \[\huge \frac{ cosecx }{ cotx+cosecx }\]
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@matricked did u get what i am saying
cosecx (cosecx +cotx) / (cosecx +cotx)^2
= cosecx/ (cotx+cosecx)
lol , i was doing a silly mistake
thank u
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hahaha lolz xD i was thinking whats going on with Udit !
hehe xD
yw
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