Question

given cos a = -24/25 in quadrant 2 and sin B = -5/13 in quadrant 3, find sin (a+B).

Answer 1

a)-36/325
b)-204/325
c)36/325
d)204/325

Answer 2

Long response so be patient.

Answer 3

Thank You :3

Answer 4

\[cosA=\frac{ -24 }{25 }=>sinA=\frac{ 7 }{25 }\]

Answer 5

\[sinB=\frac{ -5 }{13 } => cosB=\frac{ -12 }{ 13 }\]

Answer 6

\[\sin(A+B)=sinAcosB+cosAsinB\]

Answer 7

\[=(\frac{ 7 }{ 25 })\times(\frac{ -12 }{ 13 })+(\frac{ -24 }{25 })\times(\frac{ -5 }{ 13 })\]

Answer 8

If you work through this you will end up with 36/325

Answer 9

Thank you so much! this just verified my answer as well. :)

Answer 10

welcomed