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Mathematics 15 Online
OpenStudy (anonymous):

How do I solve for A in this problem?

OpenStudy (anonymous):

pic will be uploaded

OpenStudy (anonymous):

OpenStudy (anonymous):

well,you know in this graph: |dw:1405314999991:dw| how can we find angle m?

OpenStudy (anonymous):

well i'll prove it for you :)

OpenStudy (anonymous):

|dw:1405315192729:dw|

OpenStudy (anonymous):

in this graph we have M = 180 - (B1 + D2) ok?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so, M = 180 - B1 - D2 and (180-D2) is D1 so M = D1 - B1

OpenStudy (anonymous):

@Brialynn96

OpenStudy (anonymous):

Ok, I think I get it a little now

OpenStudy (anonymous):

why a little? look at the graph again

OpenStudy (anonymous):

i just divided B and D to B1 and B2 and D1 and D2

OpenStudy (anonymous):

then i'll be able to prove

OpenStudy (anonymous):

Okay, I see now

OpenStudy (anonymous):

and when we have: |dw:1405315621088:dw| A = theta , then theta is (2) arcBC

OpenStudy (anonymous):

sorry! theta is BC / 2!

OpenStudy (anonymous):

not 2 x BC

OpenStudy (anonymous):

So BC is half of theta (A)?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and we have M = D1 - B1 |dw:1405315819069:dw|

OpenStudy (anonymous):

and D1 = AB/2 and B1 = DC/2

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then \[M = \frac{ AB - DC }{ 2 }\]

OpenStudy (anonymous):

proved :)

OpenStudy (anonymous):

and you can use this

OpenStudy (anonymous):

can you do it or need help?

OpenStudy (anonymous):

@Brialynn96

OpenStudy (anonymous):

I think I can do it now, thank you

OpenStudy (anonymous):

you're welcome :)

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