Mathematics
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OpenStudy (anonymous):
How do I solve for A in this problem?
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OpenStudy (anonymous):
pic will be uploaded
OpenStudy (anonymous):
OpenStudy (anonymous):
well,you know in this graph:
|dw:1405314999991:dw|
how can we find angle m?
OpenStudy (anonymous):
well i'll prove it for you :)
OpenStudy (anonymous):
|dw:1405315192729:dw|
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OpenStudy (anonymous):
in this graph we have M = 180 - (B1 + D2)
ok?
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so,
M = 180 - B1 - D2 and (180-D2) is D1 so M = D1 - B1
OpenStudy (anonymous):
@Brialynn96
OpenStudy (anonymous):
Ok, I think I get it a little now
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OpenStudy (anonymous):
why a little?
look at the graph again
OpenStudy (anonymous):
i just divided B and D to B1 and B2 and D1 and D2
OpenStudy (anonymous):
then i'll be able to prove
OpenStudy (anonymous):
Okay, I see now
OpenStudy (anonymous):
and when we have:
|dw:1405315621088:dw|
A = theta , then theta is (2) arcBC
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OpenStudy (anonymous):
sorry! theta is BC / 2!
OpenStudy (anonymous):
not 2 x BC
OpenStudy (anonymous):
So BC is half of theta (A)?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
and we have M = D1 - B1
|dw:1405315819069:dw|
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OpenStudy (anonymous):
and D1 = AB/2 and B1 = DC/2
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
then
\[M = \frac{ AB - DC }{ 2 }\]
OpenStudy (anonymous):
proved :)
OpenStudy (anonymous):
and you can use this
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OpenStudy (anonymous):
can you do it or need help?
OpenStudy (anonymous):
@Brialynn96
OpenStudy (anonymous):
I think I can do it now, thank you
OpenStudy (anonymous):
you're welcome :)