7-3y = t^2

Differentiate w.r.t to y on both sides
@ganeshie8 @Johnbc

Question

7-3y = t^2

Differentiate w.r.t to y on both sides
@ganeshie8 @Johnbc

ganeshie8 · Answer

$$\large \dfrac{d}{dy} \left(7-3y\right) = \dfrac{d}{dy}\left(t^2\right)$$

aum · Answer

$ \Large 
\frac {d}{dy}(7-3y) = \frac {d}{dy}t^2 \ \Large
-3 = 2t\frac {dt}{dy}
$

ganeshie8 · Answer

7 is a number constant,
whats the derivative of a number with respect to variable ?

ganeshie8 · Answer

does the value of 7 change as the variable y changes ?

anonymous · Answer

I got that , but R.H.S

ganeshie8 · Answer

you have a different variable on RHS, so you need to use chain rule

anonymous · Answer

@Johnbc told we treat it as constant

anonymous · Answer

In integration.

ganeshie8 · Answer

we treat it as constant if t does not depend on y,
but here we have `t = f(y) `

anonymous · Answer

You have 2 different variables multiplied by each other in this problem so for the derivative you would need to apply the chain rule

anonymous · Answer

ohk , thanks