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7-3y = t^2 Differentiate w.r.t to y on both sides @ganeshie8 @Johnbc
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\[\large \dfrac{d}{dy} \left(7-3y\right) = \dfrac{d}{dy}\left(t^2\right)\]
\( \Large \frac {d}{dy}(7-3y) = \frac {d}{dy}t^2 \\ \Large -3 = 2t\frac {dt}{dy} \)
7 is a number constant, whats the derivative of a number with respect to variable ?
does the value of 7 change as the variable y changes ?
I got that , but R.H.S
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you have a different variable on RHS, so you need to use chain rule
@Johnbc told we treat it as constant
In integration.
we treat it as constant if t does not depend on y, but here we have `t = f(y) `
You have 2 different variables multiplied by each other in this problem so for the derivative you would need to apply the chain rule
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ohk , thanks
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