For each of the following equations, find the value(s) of the constant α so that the equation has exactly one solution, and determine the solution for each value.

x^2+αx+3α+3

To solve i set the discriminant to zero using the following coefficients
a=1
b=α
c= 3α+3

giving me
α^2-4(1)(3α+3)
α^2-12α-12

then I plugged that into the quadratic to get the two α's but my online HW is saying that it is incorrect.

Question

For each of the following equations, find the value(s) of the constant α so that the equation has exactly one solution, and determine the solution for each value.

x^2+αx+3α+3

To solve i set the discriminant to zero using the following coefficients 
a=1
b=α
c= 3α+3

giving me 
α^2-4(1)(3α+3)
α^2-12α-12

then I plugged that into the quadratic to get the two α's but my online HW is saying that it is incorrect.

ganeshie8 · Answer

that looks good to me ! must be some syntax issue with the grader

ganeshie8 · Answer

try again with `sqrt` or ()^(1/2) etc.. http://www.wolframalpha.com/input/?i=solve+%CE%B1%5E2-4%281%29%283%CE%B1%2B3%29+%3D+0

ganeshie8 · Answer

lol batman, goto sleep :P

ganeshie8 · Answer

btw, the question is asking for the solutions of given quadratic, NOT the values of $\alpha $

nincompoop · Answer

find the value(s) of the constant α so that the equation has exactly one solution, and determine the solution for each value.

ganeshie8 · Answer

yeah so try entering the value of quadratic at the $\alpha $ values

dan815 · Answer

th^

dan815 · Answer

for the solution to have just 1 root, the discriminatnt must be zero

cp9454 · Answer

ans is $$\alpha = 6\pm4\sqrt3$$

ganeshie8 · Answer

$$\large x =  \dfrac{-\alpha\pm 0 }{2}$$

dan815 · Answer

oh u just messed up your coefficient b

anonymous · Answer

looks like it just wanted me to enter in a very specific syntax, thanks all.

dan815 · Answer

no wait u didnt.... that is wierd

ganeshie8 · Answer

Ryan, what did u get for $\alpha $ ?

cp9454 · Answer

lol funny

dan815 · Answer

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