Solve 2^x - 8x + 10 = 0,x
First, divide both sides by 2. Then try factoring or using the quadratic equation.
\[2^{x} - 8x + 10 = 0,x\]
What does 0,x mean?
The points on a graph?
Solve for x
Yes I know it's solving for x but I don't understand the last part of that equation
@mathstudent55 can you shed some light on this?
The equation ends in 0. The x means solve for x.
Oh, that ",x) confused me
Think of the instructions as being: Solve each equation for the indicated variable: \(3x = 6, x\)
Yeah I usually don't see equations in that format
I've come across a few like this, that 's how I figured it out.
Sorry, I just noticed the exponent x. Forget what I wrote above. I misread it.
How would we divide by 0 though? We would get undefined
divide 0 by 2
Yeah c;
\[2^{x} - 10 = 8x\] Add 8x to both sides = 1st step?
@mathstudent55
Yeah and its plus 10!
You can use rules of logarithms to get rid of x from the exponent.
First, 0/2 is not undefined. 0/2 = 0 2/0 is undefined. Second, since this equation has an exponent of x, forget all my instructions above, including dividing both sides by 2. I misread the first term as 2x^2.
\[\ln(C^x) = xln(C)\]
The problem with taking logs is that you will end you with a sum or difference involving a variable, and we can't simplify such a log. I only know how to solve this by trying to graph it and then by trial and error to see where the zeros are.
Forgot about that 8x.
Are you sure it is not\[x^2\] @Swqaedf
Yes. It's 2^x
one solution is to graph the curve and identify the zeros... or use an approximation method... using a table of values the zeros and between 1 and 2, then 4 and 5 hope it helps
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