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Find the number of terms in the following arithmetic sequence. 1, 3, 5, 7, . . ., 51
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Looks like a(n)=1+2(n-1), n=1, a(1)=1 n=2, a(2)=3 so n=26, a(26)=1+2(26-1)=51 Therefore 26 terms in the sequence.
this is an example of an arithmetic progression, where every adjacent values have a common difference... the general formula is given by... a(n) = a(1) + (n - 1) x d where: a(1) = the value of the 1st term, a(n) = the value of the nth term, n = the number of terms in the given sequence, d = the common difference between adjacent values in a sequence....
from the solution of @DominicNg... you just plug-in the given values... and you can solve for n....
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