Learning about Geometric Sequences. How to find the nth term of a sequence?
http://aplus.sccpss.com/R85Content/media/pictures/ac_trig/d3011s1.gif?ts=1405343294480
Don't understand that..
@ganeshie8
A sequence is a series of sums. \[\sum_{n=1}^{\infty}\] The value of the term you add up each time depends on the value of n that rises per 1. The term usually consists of a coefficient (a_number) and an unknown (r). so what you got as information in what you showed you could write as if n=1 -> the term is a1 or a1(r)^0 if n =2 -> the term is equal to a1(r) if n=3 -> the term is equal to a1(r)² if n=4 -> the term is equal to a1(r)³ and so on... if you write it as a sum you would get y(total)=a1 + a1(r) +a1(r)² + a1(r)³+.... instead of writing the sum of terms like above into infinity you can see a pattern the coefficient is always a1 multiplied by r to a power. And if you look closer you'll notice that the power of r is always n-1. For y of the nth-term (to infinity) you could say that y_n=a1(r)^(n-1) But what we use as a letter for n is arbitrary... we can also use x, and make it y_x=a1(r)^(x-1)
Sorry, that should be a_y=a1(r)^(x-1) It's confusing because they suddenly use y and x. I would normally write it down as a_n=a1(r)^n-1
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