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Chemistry 19 Online
OpenStudy (anonymous):

The average kinetic energy of 1 mole of a gas at 25 degrees Celsius is: 3.72 x 103 J 3.67 x 101 J 1.65 x 103 J 3.12 x 102 J

OpenStudy (anonymous):

@ganeshie8 @tester97

OpenStudy (anonymous):

Show me how to calculate please, and then check my answer; I have more questions like this. I shall medal and fan those who help! Pretty please!

OpenStudy (somy):

\[U= \frac{ 3 }{ 2 }nRT\]

OpenStudy (anonymous):

oh wow

OpenStudy (anonymous):

i was about to tag you cause i cant remember how to do this stuff and i cant find it in my old books XD^

OpenStudy (anonymous):

this got a lot of views all of a sudden

OpenStudy (anonymous):

thnx :D

OpenStudy (anonymous):

hold on, let me plug in the value, and then I'll give my answer to see if it's right

OpenStudy (anonymous):

oooh regular kinectic energy i was about to do it for ideal gas

OpenStudy (anonymous):

do I need to convert celsius to kelvin?

OpenStudy (somy):

yes

OpenStudy (anonymous):

OK...I got 3718.22865.. right? wrong?

OpenStudy (anonymous):

oh.wait

OpenStudy (anonymous):

how do I convert that number?

OpenStudy (somy):

well look |dw:1405347706241:dw|

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