Question

The hypotenuse of a right triangle is 6 m long. One leg is 1 m longer than the other. Find the length of the shorter leg. Round to the nearest hundredth.

Answer 1

ARMYRANGERS

Answer 2

@ARMYRANGERS

Answer 3

@anonymous_user

Answer 4

@stabar

Answer 5

Ok you will have to use the \(\large a^2+b^2=c^2\)

Answer 6

https://answers.yahoo.com/question/index?qid=20100330165238AAmOnfx

Answer 7

im not sure what goes were

Answer 8

Ok so you know c

Answer 9

yea

Answer 10

Ok so you are going to do Let a = shorter leg
b = a + 1 = longer leg
a² + b² = 6²
a² + (a + 1)² = 6²
a² + a² + 2a + 1 = 36
2a² + 2a – 35 = 0
a = {–(2) ± √[(2)² – 4(2)(–35)]/2(2)
a = (–2 ± √284)/4
a = (–2 ± 2√71)/2
a = (–1 ± √71)/2
a = (–1 – √71)/2 .................. discard, negative
a = (–1 + √71)/2 = 3.7130748865881793153170699531014
a = 3.71 m..................... shorter side
b = 4.71 m..................... longer side