Question

An elevator is descending at a constant speed. A passenger takes a coin from his pocket and drops it to the floor. What accelerations would one observe for the falling coin in the following frames of reference

A. the passenger
B. a person at rest with respect to the elevator shaft

Answer 1

@Mashy

Answer 2

what do you think?

Answer 3

I thought about the answer , but it was common sense , i need a logical approach to it.

Answer 4

what do u think

Answer 5

tell me.. ur common sense answer

Answer 6

g
9.8m/s^2

Answer 7

i meant gravity (g)

Answer 8

both reference frames?

Answer 9

for both

Answer 10

can u prove it to me

Answer 11

?

Answer 12

you mean .. to calculate? :P

but logical is much better.. both are inertial reference frames.. so newtons laws work

so according to newtons law.. coin will experience mg force.. and hence it will accelerate with g.

Answer 13

But won't the acceleration of the lift affect

Answer 14

the lift is NOT accelerating .. its moving with constant speed

Answer 15

oh wait yes , thanks

Answer 16

If it was acclerating it would have been
(g+a)

Answer 17

considering the downward direction to be +(ve) right?

Answer 18

depends on which direction.. if the lift is accelerating UPwards, then yea.. you would notice the coin falling with a+g

if ur lift accelerates downwards, .. u ll see it with g-a
if ur lift goes to free fall. u ll see it with g- g = 0 (weightless.. floating around)

and if ur lift accelerates more than g down, then g- a = -ve.. u ll see the coin accelerating with that value upwards..

Answer 19

Yeah thanks!

Answer 20

no probs ;-)

Answer 21

@Mashy can u help me with one more

Answer 22

tell me!

Answer 23

i will post that afterwards

Answer 24

mashy's physics powr
YOshhhhhh

Answer 25

sure :P

thanks ikks :P

Answer 26

hahaha :P
medal+fan