OpenStudy (anonymous):

Point X is located at (2, 4), and Y is located at (−6, 10). Find the y value of the point that lies halfway between X and Y.

3 years ago
OpenStudy (anonymous):

2 7 -3 -8

3 years ago
OpenStudy (anonymous):

@ganeshie8 @Mackenzie2013 @linda3 @tester97 @wolf1728 @deshawn1

3 years ago
OpenStudy (anonymous):

@Awesome781 @Fire_Fighter_Of_Miami @tHe_FiZiCx99 @gabs15 @rockstar0765

3 years ago
OpenStudy (rockstar0765):

wow lot of people

3 years ago
OpenStudy (anonymous):

need help please !

3 years ago
OpenStudy (anonymous):

midpoint formula...

3 years ago
OpenStudy (rockstar0765):

midpoint formula forgot it

3 years ago
OpenStudy (anonymous):

?idk now to do that can you please help @Orion1213

3 years ago
OpenStudy (anonymous):

y = (y1 + y2)/2

3 years ago
OpenStudy (anonymous):

two points X and Y are given with their y-coordinates... just plug-in...

3 years ago
OpenStudy (anonymous):

so what numbers would i plug into whweer? @Orion1213

3 years ago
OpenStudy (anonymous):

for X (2,4)... y1=4

3 years ago
OpenStudy (anonymous):

for Y (-6,10)... y2=10

3 years ago
OpenStudy (anonymous):

you can solve now the y-coordinate of the point half-way the two given points...

3 years ago
OpenStudy (anonymous):

ok so y=(41+102)/2 y=52? @Orion1213

3 years ago
OpenStudy (anonymous):

i am confused @Orion1213

3 years ago
OpenStudy (anonymous):

no... it is y=(4+10)/2=14/2=7...

3 years ago
OpenStudy (anonymous):

\[y = \dfrac{y_1+y_2}{2}\]

3 years ago
OpenStudy (anonymous):

oh okay thanks @Orion1213

3 years ago
OpenStudy (anonymous):

can u help with one more? @Orion1213

3 years ago
OpenStudy (anonymous):

no problem @EmmaDrew94 ... :)

3 years ago
OpenStudy (anonymous):

Calculate the area of triangle WXY with altitude YZ, given W (2, −1), X (6, 3), Y (7, 0), and Z (5, 2).

3 years ago
OpenStudy (anonymous):

8 square units 9.4 square units 7.7 square units 12 square units

3 years ago
OpenStudy (anonymous):

@Orion1213 can u help me with this one, please ?

3 years ago
OpenStudy (anonymous):

let me recall the formula...

3 years ago
OpenStudy (anonymous):

this might help.... http://www.mathguru.com/level2/application-of-coordinate-geometry-2007101600011139.aspx

3 years ago
OpenStudy (anonymous):

ugh can u just please help me solve it?? @Orion1213

3 years ago
OpenStudy (anonymous):

ok... for given vertices W, X and Y... we can use this formula...\[Area =\frac{ 1 }{ 2 }\left| (x_a-x_c)(y_b-y_a)-(x_a-x_b)(y_c-y_a) \right|\]

3 years ago
OpenStudy (anonymous):

the a, b and c are simply the w, x and y....

3 years ago
OpenStudy (anonymous):

ok so what numbers do i plug in, i am sorry i am just so confused math is so hard. @Orion1213

3 years ago
OpenStudy (anonymous):

W or A (2,-1), X or B (6,3) and Y or C (7,0)

3 years ago
OpenStudy (anonymous):

so would the answer be 9.4then

3 years ago
OpenStudy (anonymous):

if you solve it already... cause i'm just starting...

3 years ago
OpenStudy (anonymous):

oh ok sorry... hold on @Orion1213

3 years ago
OpenStudy (anonymous):

why?

3 years ago
OpenStudy (anonymous):

i am still here i am gonna try and solve it too @Orion1213

3 years ago
OpenStudy (anonymous):

i think it's b. but i think i solved it wrong...

3 years ago
OpenStudy (anonymous):

what did u get and how did you plug them into the equation? @Orion1213

3 years ago
OpenStudy (anonymous):

ok we have it as \(x_a=2, y_a=-1\).... \(x_b=6, y_b=3\).... and \(x_c=7, y_c=0\)

3 years ago
OpenStudy (anonymous):

so what would be the answer ? @Orion1213

3 years ago
OpenStudy (anonymous):

\[Area=\frac{1}{2}\left|(2-7)(3-(-1))-(2-6)(0-(-1))\right|\]

3 years ago
OpenStudy (anonymous):

i got 11?

3 years ago
OpenStudy (anonymous):

bu that is not an answer choice so i know that's wrong

3 years ago
OpenStudy (anonymous):

\[Area=\frac{1}{2}\left|(-5)(4)-(-4)(1)\right|=\frac{1}{2}\left|-20+4\right|=\frac{1}{2}\left|-16\right|\] \[Area=\frac{16}{2}=8~ square~ units\]

3 years ago
OpenStudy (anonymous):

oh okay! Thank you so it would -8 @Orion1213

3 years ago
OpenStudy (anonymous):

no it's 8... we just take the absolute value of -16 which is 16...

3 years ago
OpenStudy (anonymous):

but there is only a choice answer of -8 not 8 @Orion1213

3 years ago
OpenStudy (anonymous):

it is 8 written in your selection above....

3 years ago
OpenStudy (anonymous):

and it's asking for the area, and it can't be negative....

3 years ago
OpenStudy (anonymous):

i have no idea where i got the negative from!! @Orion1213

3 years ago
OpenStudy (anonymous):

remember the bracket in the formula... it denotes absolute value... |-16| = 16...

3 years ago
OpenStudy (anonymous):

that is where you got the negative value...

3 years ago
OpenStudy (anonymous):

hope it's clear already...

3 years ago
OpenStudy (anonymous):

oh okay i see! Your so smart Thanks Orion! :)

3 years ago