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Find the equivalent resistance of the circuit shown in the figure. Assume that V = 24.1 V, R1 = 2.94 Ω, R2 = 6.30 Ω, R3 = 8.33 Ω, R4 = 3.91 Ω and R5 = 7.19 Ω.
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You have a series and parallel circuit. So you can use a combination of techniques to solve for the resistance: Series:\[R_t = R_1 +R_2+R_3...+R_x\] Parallel: \[\frac{ 1 }{ R_T } = \frac{ 1 }{ R_1 } + \frac{ 1 }{ R_2 } +\frac{ 1 }{ R_3 }...+\frac{ 1 }{ R_x }\]
so addthem all up?
Seems like you can do that yes.
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