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simplify 9/3-2i
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Multiply Divide by 3+2i
simply multiply divide by conjugate...
\[\frac{ 9 }{ 3-2i }\times \frac{ 3+2i }{ 3+2i }=\frac{ 9(3+2i) }{ 9-(2i)^2 }=\frac{ 9(3+2i) }{ 9-4i^2 }\] now as we know i^2=-1 so \[=\frac{ 9(3+2i) }{ 9+4 }=\frac{ 9(3+2i) }{ 13 }\] your ans.
is it \[9i/ 2+3i\]
?
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idk
may be...but i think so.
if you want i can list all the answer choices
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