Question

From a hot-air balloon directly over a target, you throw a marker with an initial velocity of -40 feet per second from a height of 180 feet. How long does it take the marker to reach the target?

Answer 1

@Whitemonsterbunny17

Answer 2

Can anybody help me!

Answer 3

s = ut + 1/2 * g * t^2
s = 180 ft
u = 40 feet / sec
g = 32 ft / sec^2
Solve for t.

Answer 4

xD

Answer 5

@aum

Answer 6

Yes? Just plug the numbers into the equation and solve for t.

Answer 7

s = ut + 1/2 * g * t^2
s = 180 ft; u = 40 feet / sec; g = 32 ft / sec^2
180 = 40t + 1/2 * 32 * t^2
180 = 40t + 16t^2
16t^2 + 40t - 180 = 0
4t^2 + 10t - 45 = 0
This is a quadratic equation that you can solve using the quadratic formula.

Answer 8

so like this







































































































































180=40t+1 2 ⋅32 2 ⋅t 2

Answer 9

4t^2 + 10t - 45 = 0
Compare it to the general quadratic formula: ax^2 + bx + c = 0
a = 4, b = 10, c = -45
Plug it into the quadratic formula: \(\Large \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a } \)

Answer 10

is the answer 90ft./sec

Answer 11

@aum

Answer 12

I don't think so. But the answer will be in seconds (not ft. / sec) as the question asks for "how long" will it take which refers to time.
You can plug in the numbers into the quadratic equation and solve for t or you can graph using either a graphing calculator or an online tool and find where it crosses the x-axis.

Answer 13

venny can u give me an answer 2 tha ques

Answer 14

@magbak hey bae I missed u

Answer 15

did u read my testimony I sent u

Answer 16

ok? I guess no response then, huh

Answer 17

@magbak