Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).
heelllpppp pleaseeee
A perpendicular bisector of a side of a triangle is a line segment that is both perpendicular to a side of a triangle and passes through its midpoint.
how would it be written out though ?
Do you know how to write the equation of a line pass through 2 given points? Do you know how to find the midpoint of a segment? Do you know how to write the equation of a line perpendicular with a given line? If you say yes for all, you can solve this problem :)
you have to find the mid- point mid-point of (x1,y1) and (x2,y2) x= (x1+x2)/2 y= (y1+y2)/2
Find the slope of the line: Slope = \(\Large \frac{y_2 - y_1}{x_2-x_1}\) Slope 'm' of the perpendicular line will be the negative reciprocal of the above. Find the midpoint of the line: \(\Large (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})\) So you know the slope of the perpendicular line and you know it passes through the midpoint. The equation of the line is: \(\Large y-y_1 = m(x-x_1)\)
i just need a quick answer i am running out of time. thaannkksss (:
i know the formulas i just need to know the answer
Sorry. Can't give out answers. I can help you arrive at the answer but you will have to do the problem yourself.
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