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How many grams of oxygen gas will react completely with a block of calcium metal that is 3.0 cm by 3.5 cm by 4.2 cm, if the density of calcium is 1.55 g/mL? Show all steps of your calculation as well as the final answer. Ca + O2 → CaO
2Ca + O2 -> CaO 3.0*3.5*4.2 = 44.1 mL 1.55 g/mL * 44.1 mL 68.36 g Ca. 68.36g/40.08g/mol 1.71 mols Ca. 1.71/2 mols O2 0.85 *16.0 g/mol 13.6 g of O2.
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