Question

Which point lies on the graph of the following piecewise function?
y = x2 if x less than or equal to 0
y = x + 1 if x > 0

(0, 1)
(-1, 0)
(-2, 4)
(1, 1)

Answer 1

@thomaster

Answer 2

@aum can you help me?

Answer 3

@dan @lacrosseplayer22

Answer 4

@mathstudent55

Answer 5

Evaluate the function for the \(x\) coordinate, then see if it matches up with the listed \(y\) coordinate.

Answer 6

@SithsAndGiggles could you explain to me?

Answer 7

For instance, check \((1,1)\). \(x=1\), so and you plug it into \(f(x)\) and you get \(f(x)=y=1\), then this point is on the graph.

\(x=1\) is greater than 0, so you use the linear part, \(f(x)=x+1\).
\[f(1)=1+1=2\]
When \(x=1\), \(y=2\), so \((1,1)\) is not on the graph.

Answer 8

oh could I just draw the tables

Answer 9

What do you mean by tables?

Answer 10

I learned a way with table where you use numbers

Answer 11

lol that's not helpful, but let you use that then we can see what you did and compare methods. Just a sec :)

Answer 12

It sounds like the same method in principle, you plug in numbers and arrange them in a table.

Answer 13

oh I got 1,1 was that right

Answer 14

No, I eliminated that one. \(1>0\), so you use \(f(x)=x+1\).

Answer 15

umm. hmm

Answer 16

I plugged in different numbers into each function and got that both functions are the same at 1, 1

Answer 17

wait never mind I stuck

Answer 18

\[y=\begin{cases}x^2&\text{for }x\le0\\x+1&\text{for }x>0\end{cases}\]
Take a look at the graph: