Question

Add the following and simplify your answer

Answer 1

\[\frac{ 2v ^{3} }{ 9a ^{2}c ^{3} } + \frac{ a^{2}y ^{3} }{ 12ck} \]

Answer 2

yikes
is there really a \(k\) in the denominator?

Answer 3

yes

Answer 4

\[\frac{ 2v ^{3} }{ 9a ^{2}c ^{3} } + \frac{ a^{2}y ^{3} }{ 12ck}\] denominator must be \(36a^2c^3k\)

Answer 5

\[\frac{ 2v ^{3} }{ 9a ^{2}c ^{3} } + \frac{ a^{2}y ^{3} }{ 12ck}\]
\[\frac{4\times 2v ^{3} \times k}{ 36a ^{2}c ^{3}k } + \frac{ 3\times a^{2}\times a^2y ^{3}\times c^2 }{ 36a^2c^3k}\]

Answer 6

multiply out and add in the numerator

Answer 7

okay, let me try

Answer 8

here is my new equation \[\frac{ 8v^{3}k+3a^{4}y^{3}c^{2} }{ 36a^{2}c^{3}k }\], now how can I simplify or reduce this?

Answer 9

I don't think that can be simplified any further.

Answer 10

Well I think you can subtract the variables.

Answer 11

@satellite73 what do you think?

Answer 12

You can't because neither of the factors of the numerator "both" have any of the variables.