(2x^2)^4
helo, helpp.?
do you know that the exponent means multiply by itself that many times? (2x^2)^4 means multiply (2x^2) by itself 4 times. Like this: (2x^2)(2x^2)(2x^2)(2x^2)
when you multiply, you can change the order, so you could write it 2*2*2*2 * x^2 * x^2 * x^2 * x^2
or, knowing that x^2 is x*x 2*2*2*2 * x*x* x*x* x*x* x*x
so i multiply the whole number ? and the exponent?
most people would use the short-cut exponent idea to rewrite x*x* x*x* x*x* x*x that is x times itself how many times ?
8
so its 16x^8?
and though you could write 2*2*2*2 as 2^4 (using the exponent idea) most people would just multiply it out and get 16
so i always multiply the exponents?
yes, 16x^8 there is a short cut to doing the problem \[ \left(2 x^2\right)^4 = 2^4 \cdot \left(x^2\right)^4 \] we apply the exponent to each factor. then we use this "rule" \[ \left(x^a\right)^b= x^{ab} \] to get \[ 2^4 \cdot \left(x^2\right)^4 = 2^4 \cdot x^8 = 16 x^8\]
okay so is that a yes ialways multiply the exponents?
you don't multiply exponents. play with the idea a few minutes. example: x^2 * x^2 means x*x * x*x = x^4 notice the 2+2= 4 or x^1 * x^3 = x* x*x*x = x^4 1+3 = 4 it's a nice short-cut to remember.
What if i have (81m^8)(4m^6) I do 81 x 4 and 8 x 6?
you do multiply exponents if you have \[ \left(x^a\right)^b \] you can remember this by remembering a simple example. if a is 1 and b is 3: \[ \left(x^1\right)^3 = x^1 \cdot x^1 \cdot x^1 = x^3 \] (the 3 means multiply the stuff in the parens by itself 3 times)
or do i add the exponents in that case?
(81m^8)(4m^6) that means 81 * 4 * m^8 * m^6 so 4*81= 324 is correct m^8 * m^6 remember that means x*x*x*x*x*x*x*x and m^6 means x*x*x*x*x*x so m^8 * m^6 means x*x*x*x*x*x*x*x * x*x*x*x*x*x which, using the exponent short-cut is written x^14 it should make sense we add exponents when you multiply x^8 * x^6 = x^14
ohhh okay i think i got it
if you do the problems by "expanding" the exponents, it becomes more clear what the answer should be. And because it's so much work, you will learn the exponent idea pretty quick (because it's easier)
HOw do i simplify This tho 2^12/2^10
its supposed to be a fraction
I'll do 2^3 / 2^2 as an example \[ \frac{2^3}{2^2} = \frac{2\cdot 2 \cdot 2}{2\cdot 2} =2 \] because 2/2 = 1, and we can simplify two 2/2 leaving just one last 2 if we look at the exponents, 3 -2 = 1 notice we subtracted exponents (that is the fast way)
2^12 will have 2*2*2*2*2*2*2*2*2*2*2*2 divided by 2*2*2*2*2*2*2*2*2*2 (if I counted correctly) the 10 2's in the bottom will "cancel" 10 2's up top, leaving two 2's left over or using the exponent idea: 2^(12-10) = 2^2 =2*2 = 4
confusing ?
Join our real-time social learning platform and learn together with your friends!