Question

2/3(x-7)=3/4(4x-5)

Answer 1

cross-multiply \(\bf \cfrac{2}{{\color{brown}{ 3(x-7)}}}=\cfrac{3}{{\color{brown}{ 4(4x-5)}}}\implies {\color{brown}{ 3(x-7)}}\cdot 2=3\cdot {\color{brown}{ 4(4x-5)}}\)

and solve for "x"

Answer 2

hmm I got it a bit backwads there.. .lemme fix it quick

Answer 3

\(\bf \cfrac{2}{{\color{brown}{ 3(x-7)}}}=\cfrac{3}{{\color{brown}{ 4(4x-5)}}}\implies 2\cdot {\color{brown}{ 4(4x-5)}}={\color{brown}{ 3(x-7)}}\cdot 3\)

Answer 4

The answer is 3(x-7)x3?

Answer 5

hmm not quite.. you need to distribute and solve for "x"

Answer 6

well, i got x = -43/29

Answer 7

hmmm

Answer 8

\(\bf \cfrac{2}{{\color{brown}{ 3(x-7)}}}=\cfrac{3}{{\color{brown}{ 4(4x-5)}}}\implies 2\cdot {\color{brown}{ 4(4x-5)}}={\color{brown}{ 3(x-7)}}\cdot 3
\\ \quad \\
2\cdot (16x-20)=(3x-21)\cdot 3\implies 32x-40=9x-63
\\ \quad \\
32x-9x=-63+40\implies 23x=-23\implies x=\cfrac{-\cancel{ 23 }}{\cancel{ 23 }}\)

Answer 9

The solution is all real numbers?

Answer 10

Or no solution?