Use the substitution method to solve the following system of linear equations: 2x + 2y = 10 x = –y + 5 A. The solution is (4, –1). B. There is no solution. C. There are an infinite number of solutions. D. The solution is (2, –3).
@iPwnBunnies @Luigi0210 @wolfe8 @phi @Whitemonsterbunny17
Add 'y' to both sides of the second equation, and you'll see. Plus, you can factor something. c:
Is it D?
wait.... A?
@dan815
What did you find out when you added 'y' to both sides? .-.
Idk! >.< I dont understand how to do this at all
.-. Just do what I say, add 'y' to both sides in the second equation. 2x + 2y = 10 x + y = 5 Can you factor something out of the top equation?
um... 10?
or is it 5?
._. What factor do 2x and 2y share?
2
you multiply them by 2?
Right! :D 2x + 2y = 10 2(x+y) = 10 Can't we also factor out a 2 out of the 10? 2(x+y) = 2(5)
sorry im back and im kind of confused what to do next
Well, you have a 2 factor on both sides. You can cancel them out. ._. You're left with x + y = 5 The same as the second equation. The first equation is just a multiple of the second equation. They would graph the same line. c:
oh, ok so C
Yep.
Thanks dude! Really helped me out =D got an 88% :D
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