. The diagram shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 6.3 N and the angle between them is 40°, what third force will cause the object to be in equilibrium?
Plz help. Thanks
|dw:1405392077410:dw|
Now to establish an equilibrium we will have to apply a force equal and opposite to the resultant of these two forces.|dw:1405395048987:dw|
Resultant of the given two forces is given by 2\(\times\)6.3\(\times\)Cos\(\large\frac{40}{2}\)
Thanks so much
\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)
I also posted this question: You push against a steamer trunk with a force of 800 N at an angle alpha with the horizontal . The trunk is on a flat floor and the coefficient of static friction between the trunk and floor is 0.55. The mass of the trunk is 87 kg. What is the largest value of alpha that will allow you to move the trunk? Would appreciate some help
Post it as a new question please !
Okay Its up
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